8x^2+8x-1728=0

Solution for 8x^2+8x-1728=0 equation:

8x^2+8x-1728=0

a = 8; b = 8; c = -1728;
Δ = b2-4ac
Δ = 82-4·8·(-1728)
Δ = 55360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{55360}=\sqrt{64*865}=\sqrt{64}*\sqrt{865}=8\sqrt{865}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{865}}{2*8}=\frac{-8-8\sqrt{865}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{865}}{2*8}=\frac{-8+8\sqrt{865}}{16}
$